## Friday, August 3, 2007

### quat

these r the only questions for the new commers to this thread i have collected some of them
1) -1y-x and y-x3) was easy i m not remeber it.
4)it is from quant thred discussed many times ans is 812
5) DI question my god dam hard i spend almost 7 min to find the ans the ans is 6500
6) DI ans is 1/4
7)probablity question : they have given 3 bags all have red and white marbles: in first bag 4r n 6w second bag : 5r , 6w and third bag 5 red 5 w , they asked: if one marble is taken from first bag and tarsfer to second bag what is the probablity that it is red?( they gave numbers to the bag so no need of third bag it is just for confusion)

the ans is :(4c1/10c1 * 6c1/12c1)+ (6c1/10c1 * 5c1/12c1)

8)DI EASY ......
9)DI
10&11) DI it is of the car buyers 1st ans 450 and second answer don't remember
12)that percentile question (rosa) i m still confused marked it as d but i m not sure
13) dame easy a: (-7)^(-2) b:0
14) t is the question of trinagle inscribed in hexagon and find the area of the shaded region ans is 12 root 3
15)this is the most time difficult question of my quant it is the word problem and it is about 10 lines long i have to read 4 times to even understand it but finally i got the ans and ans is 4 (im sure about this ans)
16)then 4 or 5 question from the feedback which r easy
how many of the cubes are eqqual to the no of squares!!
ANS:12

a 5-ltrs jug contains 4-ltrs of salt water solution that is 15% salt..if 1.5 ltrs of solution spills out of the jug,,n the jug is then filled to capacity wth water,,approximately what % of resulting solution in the jug is salt?
a)71/2 % b)93/8 % c)101/2 % d) 12% e)15%
ans 12% posted by sme1

integer (x - 1) is a prime number between 40 and 50.
Column A: The sum of all different prime factors of x

concider 41,43,47 as prime no’s……tthen x=4

### gre

1. QUATRAIN:STANZA
A stanza or poem of four lines : One of the divisions of a poem, composed of two or more lines usually characterized by a common pattern of meter, rhyme, and number of lines.
2. BOOTLESS:FUTILE
Without advantage or benefit; useless : Having no useful result.
3. FUSTIAN:BOMBASTIC
pompous lanuage : pompous speech or writing.
4. INFINITUDE:MEASURE
An immeasurably large quantity : Dimensions, quantity, or capacity as ascertained by comparison with a standard
5. CISTERN:LIQUID
A receptacle for holding water or other liquid, especially a tank for catching and storing rainwater :
6 LOCK:SECURE
7. VIVID:INTENSITY
Having intensely bright colors: Exceptionally great concentration, power, or force
8. DEBASE:STATUS
To lower in character, quality, or value; degrade : Position relative to that of others
10. RESONANT:SOUND
Strong and deep in tone; resounding :
11. JUDGE:LAWS
To form an opinion or estimation of after careful consideration
12. UNSWERING:VACILLATE
: To swing indecisively from one course of action or opinion to another
13. CAJOLING:RELUCTANCE
To urge with gentle and repeated appeals, teasing, or flattery; wheedle : The state of being unwillingness
14. SLOTHFUL:ASSIDUITY
Disinclined to work or exertion; lazy : Attentive care
17. FRILL:SUPERFLUITY
things that are not necessary but are added to make sth more attractive or interesting: : more than you need or want
To exhibit affection or attempt to please : To exhibit affection or attempt to please
19. ALLAY:RELIEVE
To reduce the intensity of : To free from pain
21. DISSEMBLER:FORTHRIGHT
To make a false show : straight forward
26. STOLID:IMPASSIVE
Having or revealing little emotion : Revealing no emotion
27. MARTINET:LENIENT
One who demands absolute adherence to forms and rules : Inclined not to be harsh or strict
29. OVERTURE:INTRODUCTION
An introductory section or part, as of a poem; :
30. FUTON:BED
mattress :
31. MISCREANT:WRETCHED
villain : of very poor quality or condition;
33. SAGA:ANECDOTE
a long traditional story about adventures and brave acts, especially one from Norway or Iceland : A short account of an interesting or humorous incident
34. RAUCOUS:HARSH
Rough-sounding and harsh :
35. ORCHESTRA:MUSICIAN
A large group of musicians who play together on various instruments : One who composes, conducts, or performs music, especially instrumental music
36 BUMPTIOUS:ASSERTIVE
howing that you think that you are very important; often giving your opinions in a loud, confident and annoying way : expressing opinions or desires strongly and with confidence, so that people take notice
39. MISCREANT:CRIMINAL
An evildoer; a villain.
40. Anachronistic:time :: Discordant:sound
41. FERVOR:ZEALOT
improvidence:Spendthrift
42. TERSNESS:SUPERFLUOUS
spontanity:studied
43. DISINFECTENT:GERM
substance that disinfects : a very small living thing that can cause infection and disease:
44. PERCIPENT: DISCERNMENT
having or showing the ability to understand things, especially things that are not
obvious : the ability to show good judgement about the quality of sb/sth
45. NIMBLE:CLUMSYNESS.
able to move quickly and easily : moving or doing things in a very awkward way:
46. FLUIAL:RIVER.
Something tech. connected to river :
47. SOOTHE:CALM
o make sb who is anxious, upset, etc. feel calmer : not excited, nervous or upset
48. ENFEEBLE:STRENGTH
to make sb/sth weak :quality of being strong
49. SEDULOUS:DILIGENT.
showing great care and effort in your work : showing care and effort in your work or duties
50. ALLAY:RELIEF
to make sth, especially a feeling, less strong: :
51. VAULT:VALAUBLES
a room with thick walls and a strong door, especially in a bank, used for keeping valuable things safe : things that are worth a lot of money
52. STATURE:TALL
the importance and respect that a person has because of their ability and achievements
a person who treats sb more important with special kindness or respect in order to gain their favour or help : to say nice things about sb, often in a way that is not sincere, because you want them to do sth for you or you want to please them
57. PIQUE:ASSUAGE
annoyed or bitter feelings that you have, usually because your pride has been hurt : to make an unpleasant feeling less severe
58. PIQUANT:INSIPID
having a pleasantly strong or spicy taste : having almost no taste or flavour
59. DORMANT:VIGOR
not active or growing now but able to become active or to grow in the future : energy, force or enthusiasm
60. RETICENT:GARRULOUS
unwilling to tell people about things : talking a lot, especially about unimportant things
61. BUMPTIOUS:ASSERTIVE
howing that you think that you are very important; often giving your opinions in a loud, confident and annoying way : expressing opinions or desires strongly and with confidence, so that people take notice
62. SAGA:NARRATIVE
a long story about events over a period of many year : a description of events, especially in a novel

## Wednesday, July 25, 2007

### quant recent

3) a sphere with a radius of r=1 metre....it is revolving around its vertical axis and completes one rotation in 1 second.....find the speed at which it is rotating and it is in the range ofa)0 to pieb)1 to piec)0 to 2pied)1 to 2pie

the prob was sumthing like....the price of X was 5 times the price of Y and sales of Y=4 times sales of X.amt received frm sales of Y equal to 36\$\$...i dunno if the soln is given coz upto post no 501 there was none so am givin my version!!let Px and Py be price of X and Y respsimly Sx and Sy be sales of X and Y respwe have.. Py*Sy=36 (coz Py*Sy gives amt recvd frm sales of Y)for amt recvd frm sales of X----Px*Sx=(5Py)*(.25*Sy)=5/4*Py*Sy=5/4*36=20i think this is right...wat say??

parallegram opposite angles are given 7x,120another angle 3ycola col bx yanswer is x=17.14y=20thus Bam i right?

14) 1,1,11 2,2,22colA s.d of first setcolB s.d. of othr setans B15) In a plane ,given l and n lines are parallel.given n equation as 2y+3x=4then wat is the slope of m?16) A circle is inscribed in a square.col A colBdiameter of circle diagonal of square17) a line and circle lie in a single plane......the line passes through the circle.......column ait meets the circle at no.of pointscolumn b 218) word problems-----like ther is some company...it produced 30% new products last year.in that 60% were sold.what is the % of new pproducts didnt sold?

14)sd of first set =(1+1+11)/3=13/3sd of second set=(2+2+22)=26/3so Ans is B15)the standard form of equation of line is y=m*x+cso slope =-a/b16)The ans is B as the diameter of the circle is a(length of the side) and the length of the diagonal is sqrt2*a17)Ans B as a st line can pass through 2 pts only on a circle

daily wages : 5 10 15 20 25 30
totalnumber of persons: 7 12 37 25 22 11 114
find da median o this freq distribans :2o

5:12 am(22 minutes ago)
ABC is a triangle AC is the base angle B=60,c=45 and a perpendicular is drawn from A to bc and AB=1
col A col B
BC sqrt3
ans is b

14) 1,1,11 2,2,22colA s.d of first setcolB s.d. of othr setans B15) In a plane ,given l and n lines are parallel.given n equation as 2y+3x=4then wat is the slope of m?16) A circle is inscribed in a square.col A colBdiameter of circle diagonal of square17) a line and circle lie in a single plane......the line passes through the circle.......column ait meets the circle at no.of pointscolumn b 218) word problems-----like ther is some company...it produced 30% new products last year.in that 60% were sold.what is the % of new pproducts didnt sold?

A put his amount on x pecentage of intrest while B put some amount on x/2 percentage of intrest .A getting d dollars as intrest and B getting 2d dollars on intrest..(this was long narrated Q. i have writtn in brief)colA amount of AcolB amount of Bwats d xact ans 4 tis

series 11,1, 11 series 22,2,22 col A-->std. deviation of series 1col B-->std. deviation of series 2Ans: I am gettin B as d ansA--->SQR ROOT OF 200B--->SQR ROOT OF 369

the diagram ' xy plane problem' in my orkut album [http://www.orkut.com/Album.aspx?uid=4292267246257639284]
..==> f(1.3)= ?a)f(-0.3) b)f(-0.7) c)f(-1.3) d)f(0.3) e)f(0.7)Ans: (b)
2) The ladder problemA ladder of 5 ft length is in a slant position against a wall. The base of the ladder ispulled y ft away from the wall and so the top of the ladder moved x ft towards the ground.Refer to the diagram ' ladder problem' in my orkut album [http://www.orkut.com/Album.aspx?uid=4292267246257639284]..col a:--->xcol b:--->yAns: D( please verify this.. I'm not sure)

A put his amount on x pecentage of intrest while B put some amount on x/2 percentage of intrest .A getting d dollars as intrest and B getting 2d dollars on intrest..(this was long narrated Q. i have writtn in brief)colA amount of AcolB amount of B

= [(123)^4]-[(123)^3]+[(123)^2]-(123)

if z is divided by 122 what is the remainder?

0....1....2....3....4

Ans: 0

2)

the vertices of square S are (-1,-2), (-1,1), (2,-2) and (2,1)
what is the point where the diagonals of the square S meet?

Ans: (1/2, -1/2)

3)
series 1
1,1, 11
series 2
2,2,22

col A-->std. deviation of series 1
col B-->std. deviation of series 2

Ans:

4)
For road widening the length of a rectangular plot is decreased by 15% and its breadth is

increased by 15%.
col A-->area of the original plot
col B-->area of the changed plot

5)k is a +ve integer. The function f(x) is defined as
f(x)= remainder when x is divided by k
==> f(x) = x%k

then what is the value of k , if f(k+25)=3

Ans: 21 (please verify for any other)

6)
two cylindrical containers are there. one with internal radius 3 inches other with internal radius 6 inches. The 3 inch cylinder is of 10 inch height of which upto 9 inches was filled with a liquid. what would be the depth of the the liquid in the 2nd container if 1st container is emptied into the second container(previously empty)

Ans: 2.25 inches

I dont think the Qn is correct but it is similar... just u shud know the volume of

cylinder to solve this.. sorry if the Qn is wrong.

7) xy>0

col a:--> y
col b:--> 0

Ans: D
i might have answered wrong to the previous two questions. thats why i got this kind of easy Qn

8)A ladder of 5 ft length is in a slant position against a wall. The base of the ladder is

pulled y ft away from the wall and so the top of the ladder moved x ft towards the ground.

col a:--->x
col b:--->y

Ans:

9) if k is an integer and 33≤k≤35

then what is the probability of some s***..
the problem is about prime factors <13
sorry... don't remember the exact Question. but the Answer is (3/10)
i'll post the exact Question when ever i remember it.. by the time i post it some one might give the correct question

all aug quant appeared so far r here
1)x+y=8 and xy=12 thn column A x(1+y)+y column B 20

2)There are 24 oranges in 1 bag.and 8 bags in 1 box then how many dozens in 24 boxes.

Ans) 1 bag contains 2 dozens
1 box contains 2*8=16 dozens
24 boxes contains 24*16=384 dozens
3) a sphere with a radius of r=1 metre....it is revolving around its vertical axis and completes one rotation in 1 second.....find the speed at which it is rotating and it is in the range of
a)0 to pie
b)1 to pie
c)0 to 2pie
d)1 to 2pie

4) there are "r" sections and each section is divide into "t" no.of fields and beth n jordan water these fields everyday ...if on monday beth does his share of watering and also 1/3 of jordans work.......then
column a column b
beths normal share rt/4
of work

5) ann deposited \$10,000 for x yrs at an interest of 6%.... while david deposited \$ 12,000 for y yrs at interest of 4.5%......
col A col B
amnt ann earned amnt david earned
Ans) as column a : 10000(1.06)^x
and column b: 12000(1.045)^y

x and y can take any value greater than 0 D

6) 3}A CIRCLE WAS INSCRIBED IN A SQUARE.AREA OF SQUARE IS 36PIE.WHAT IS THE AREA OF CIRCLE.

7) I DONT REMEMBER NAMES BUT LET THEM BE A,B,C.AGE OF A IS TWICE THAT OF B AND HALF OF
Ccola: col b:
average arthimethic mean of their ages 3

8) n>1
colA colB
115n 215(n-1)
ans) is D

9) z>y>x>1
colA colB
z(x+y+1) y(x+z+1)
A

10) A()B=-A^2B then find 2()-1
problem on symbol
ANS) -1/4

11) 1)5col A /x/ col B /y/

12) colA col B
2^7 *5^4 10^4*2^3

13)A put his amount on x pecentage of intrest while B put some amount on x/2 percentage of intrest .A getting d dollars as intrest and B getting 2d dollars on intrest..(this was long narrated Q. i have writtn in brief)
colA amount of A
colB amount of B

## Tuesday, July 3, 2007

### quant

2.G gallons of water in a tank, if X gallons/hr--water flowing inward,Y gallons/hr water flowing outward, condition Y>X.Then how much time it takes to so that the tank capacity becomes G/2 gallons of water.
ANS:g/2(y-x)
{
{G gallons of water in a tank, if X gallons/hr--water flowing inward,Y gallons/hr water flowing outward, condition Y>X..then how much time it takes to so that the tank capacity becomes G/2 gallons of water. In Flow rate = x g/hr Out Flow rate = y g/hr so it will be taken as negative Total time to fill G gallons of water is = -yx/x-y but the question is asking for half capacity then time will be = -yx/(x-y)2 as y is greater than x so the whole answer will become positive so t= xy/(y-x)2}
}
its a standard formula to calculate time for such tank ques like suppose A is inward rate to fill tank of particular capacity suppose B is outward rate to fill tank of particular capacity Total time will be A(-B)/(A-B )
}
sequence was given to be S=5,-5,5,-5,5,-5......k..(k can be 5 or -5) what is the number of terms in the series for which the arithmetic mean is 1/9.. a. 5 b. 15 c. 29 d. 45 e. 38 answer (D) i.e., 45
{
If r = (3p + q)/2 and s = p - q, for which of the following values of p would r^2 = s^2? A. q/5 B. 10 - 3q/2 C. q - 1 D. 3q E. 9q/2 - 9 this one is very easy.. Condition is r^2 = s^2 substitute & you'll get (3p+q) ^2/4 = (p-q) ^2 solve to get a quadratic equation in terms of p & q 5p^2 + 14pq - 3q^2 = 0 solve this equation for p; you’ll get values as -3q & .2q (=q/5) since q/5 is available answer is a
Five years ago, Beth’s age was three times that of Amy. Ten years ago, Beth’s age was one half that of Chelsea. If C represents Chelsea’s current age, which of the following represents Amy’s current age? 1. c/6 + 5 2. 2c 3. (c-10)/3 4. 3c-5 5. 5c/3 – 10
Chelsea's current age is C. 10 yrs back...chelsea's age will be C-10. 10 yrs back..given that Beth will be half of Chelsea. So C-10/2. 5 yrs back Beth's age will be (C-10)/2 +5) =C/2 which gives C/2. Let us assume that Amy's current age is x.5 yrs back it will be x-5.Given that Beth will be 3 times as that of Amy 5 yrs back..,so 3x-15. So now equate Beth's age in terms of Amy and Chelsea 5 yrs back.... 3x-15=C/2 3x=C/2 + 15 3x=(C+30)/2 x=(C+30)/6 X=C/6 + 5 is the answer......
Three strings of musical instrument vibrates 6,8 and 12 times a second respectively. if all the three begins to vibrate simultaneously, find the shortest time interval before all the three vibrate together again... a) 1/4 s 2)1/2 s 3)24s 4)48s 5)96s
as its given that one string vibrates 6 times in 1 sec. so it vibrates once in 1/6 sec same for second string @ 1/8 sec. third string @ 1/12 sec now the shortest time interval can be derived by finding the hcf of all three above that gives u 1/2 sec.
{{{
3^n + 4 is divisible by 5 find the value of n a) 23 b) 24 c) 25 d) 26 e) 27 Any number which is divisible by 5 has 5 or 0 in it's units place...so 3^4 should have 1 or 6 in it's units place so that the last digit of 3^n + 4 is 5 or 0...So we have to find out by checking the options.... 3 has a series of 3,9,7,1(units place of powers of 3..,this series is a cyclic one)... Let me explain.... a) Lets verify option a..., 3^23.., so 23 divided 4(dividing by 4 because .., 3 will be having 4 different numbers in it's units place...) gives 3 as a remainder..,so 3rd number of the sequence(3,9,7,1)..so 7 is the units digit of this 3^23...,so 7+4 =11....,1 will be in unit's place..,which is not divisible by 5... so this is not the answer... b) 3^24.., 24 divided by 4 gives a remainder 0..., if we get the reminder 0.., we should take the last number of the sequence...so last number of sequence means 1..so 3^24 has 1 in its units place... so 1+4 gives 5 in it's units place.., so the number is divisible by 5.... So b is the answer.... the other options are not satisfying too... So option b is the answer...
one question on Standard Deviation K--(p,2p,3p,4p...) R--(p+5. 2p+5,3p+5, 4p+5..) col a Standard deviation of K col b Standard deviation of R
(ans c)
if -1 < x <0 then which of the following has the least possible value a) x b) 2x c) x^2 d) x^3 e) x^3 – 1
Check for x=-0.9 and x=-0.1
For x=-0.9 2x=-1.8 x^3=-0.729 (x^3)-1= -1.729 in dis least value is of 2x
For x=-0.1 2x=-0.2 x^3=-0.001 (x^3)-1=-1.001 in dis case leas value is of (x^3)-1
Don’t remem the framing of question but it is like .given 10THE MULTIPLES OF 7 ARE 7,14,21,28,35,42...AND SO ON BUT 5 IS ADDED TO IT SO THAT RESULT SHOULD BE BETWEEN 10 AND 43 ...SO IT IS POSSIBLE FOR 14+5,21+5,28+5,35+5 THERE ARE 4 POSSIBILTIES...EASY FOR EVERY ONE SORRY FOR NOT FRAMING PROPERLY WHICH MADE U CONFUSE

A rectangle was given and two circles are drawn inside the rectangle such that each circle touches the three sides of the rectangle having radius 'c' and each circle passes through the centre of the other
A TRIANGLE IS GIVEN IN CO-ORDINATE AXIS IN TERMS OF ORDERED PAIRS AND ASKED TO COMPARE ITS ANGLE WITH THE COLUMN BE WHICH WAS GIVEN 90..
ANS:
JUST TO FIND THE SLOPE OF TWO LINES AND APPLY IT IN TAN (A) FORMULA AND COMPARE
TWO TESTS WERE GIVEN 1 AND 2 IN A TEST OF 1000 STUDENTS AND AVERAGE WAS 250 AND 260 AND THE PERCENTILE OF (THINK )ANIL GOT 90TH IN TEST 1.SO ASKED TO COMPARE THE PERCENTILE WITH THE SECOND ONE.
ANS.
OPTION D
BCZ WE CANNOT COMPARE THE PERCENTILE OF TEST 1 AND WITH TEST 2 BCZ PERCENTILE IS THE NO OF PEOPLE BELOW THE REQUIRED PERSON.PLZ CORRECT ME IF I AM WRONG
A container can hold water with capacity ‘g’ gallons. At 1'o clock in the afternoon, at one point the water is flowing in at a rate of 'x' gallons/sec and at an another point water is flowing out at a rate 'y' gallons/sec. If 'x' < 'y' , how much time after 1'o clock in the afternoon will the take for the container to fill up by g/2 gallons ? (A) g/(2x-2y) (B) g/(2y-2x) (C) (2x+2y)/g (D) (2x-2y)/g (E) x+y/g
A circle C is shown which passes through (1,6) with origin O lying inside C. The center of the circle is shown C'. Col A = radius of C ; Col B= sq.root(37). The obvious answer is D.
A right triangle ABC inscribed in a circle O with legs 6,8 is shown. The question was to estimate the length of the BO. Triangle ABC is right angled at B.
Ans:
(6*2+8*2)*1/2=10
10 is the diameter. Therefore radius =10/2=5. (note:*=square root)
In the sequence a1, a2, a99, each term from a2 is one more than the preceding. The sum of all the terms is 99. Find a1
If a=pi; the sequence a, 2a, 3a, is given. Let 'x' be any number from the above sequence and 'x' not equal to 'a'. Col A ColB The ratio of x to the preceding term of the difference of x and it's the sequence. Preceding term of the sequence.
A triangle ABC is given such that AC=13, BC=12 and perimeter of triangle is 32 cola colb angle B 90 Ans: C
There are 5 envelopes for prize distribution of which 2 contain cash & 3 contain certificates. when randomly 2 envelopes r taken without replacing one after other what is the probability of getting at least one envelope which contain cash.
Solution:
For at least one envelope to contain cash:
Let for one chance be that both envelope contains cash = 2c2 now for one containing cash and another certificate the possible probability = 3c1*2c1 Hence the total probability of getting at least one envelope with cash is: (3c1*2c1+2c2)/5c2 = 6+1/10 = 7/10 hope u get it Ans: 7/10
There is a 4 by 4 by 4 cubes; it is painted on all its 6 faces. Then it is cut in 1 by 1 by 1 cube. Now u randomly picks a cube and then in that cube u randomly pick a face. Whats the prob that it is colored. Ans: 16*6/64*6=1/4
this is with regards to the cube problem....guys ull r js complicating a simple logic. To find total no. of coloured faces: On each face of big cube (4x4x4 cube) there are 16 faces of small cubes (1x1x1 cubes). Now total no. of faces of big cube=6. Therefore, total no. of coloured faces=16x6. its as simple as that. Total no . of faces=64x6 (because 64 small cubes) Total no. of faces with no colour=(64x6)-(16x6)=48x6=288 Now u can find the probability for any damn question askd.
If 15 nos have mean m and std dev s; m>s, if 25nos have mean n and std dev l ;n>l, then if the two sets combined of 40 elements has std dev c and mean d cola colb c d
The perimeter of a right isosceles triangle is 1+root2.what is the area of the triangle.
In a sequence a number is one greater than the preceding number. there are 99 numbers in the sequence and the sum of the 99 number's is 99 what is the 1st number in the sequence.
There are 4 faculty and 5 students. in how many ways a group of 1 faculty and 3students be formed.
3/4 of a company is part-time employees and 3/8 employees are temporary colA colB what part of employees are part-time and not temporary ½
Soln: if we take 32 then 3/4*32=24 & 3/8*32=12 12 are included in 24 so, only part time workers are 24-12=12 ratio= 24/32=0.375 & col b 1/2 = 0.5 So,ans is B
3/4 part-time employees. Hence 1/4 full-time employees. 3/8 employees are temp (these cud be part-time or full-time) we dont know for sure how many are part-time n how many full-time. We cannot assume that all temp employees are part-time employees (wich most ppl hav done n wrongly concluded tht ans. is B) Insufficient Data. Hence ans. D
If -1 < x <0 then which of the following has the least possible value a) x b) 2x c) x^2 d) x^3 e) x^3 – 1 Ans: D
A circle C is shown which passes through (1,6) with origin O lying inside C. The center of the circle is shown C'. Col A = radius of C ; Col B= sq.root(37). The obvious answer is D.
U is sum of first 100 even numbers V is sum of first 100 odd numbers cola-> U-V col b-> 100
Ans:
Even starts from 0, so, sum of even = [n (2*a + (n - 1) *d)] / 2 => 9900 sum of odd = ------- do ------------------------ => 10000 u - v = 100 so the both columns are equal
In a certain survey, each of 800 people expressed their attitude to A and B. They can say yes, no, or unsure. If 200 people said yes to A but not to B, how many people said yes to either A or B? the answer could be data insufficient.
One yr before Mr.Pamel age was 4 times of her daughter's age. After 6 yrs Mrs.Pamels age will be 9 yrs more than twice the age of her daughter. what is her daughters present age
let p-age of Pamela d- age of her daughter now 1 year back age of pamel is 4 times tht of her daughter hence, (p-1) = 4(d-1) --> p= 4d-3 now after 6 years age of pamel is 9 more than two times of her daughter, hence, p+6 = 2(d+6)+9 ---> p = 2d + 15 equating above equations u get ans. 9
A store sells newspaper A at price of \$1 and B at price of \$1.25. In a certain day, if r percent of the total income is from A, and p percent of the total copies sold are A, in terms of r, p=?
Let x be the no of papers sold for A Let y be the no of papers sold for B So the total number of papers sold r x+y since p% of the total copies sold are A x=p(x+y)/100 now the total income is (1*x+1.25*y)=(x+1.25y) now r% of the total income is from A x=r(x+1.25y)/100 solving the 2 equations for eliminating x and y we will get p=500r/(400+r)
(1000+1),(1000+2),(1000+3),(1000+4) is divisible by which number a) 4 b) 6 c)12 d)24 e)16 solution: just do the multiplication of the last numbers:: that’s:: 1.2.3.4=24 now from the options given 24 is divisible by all numbers... except 16..
a jar contains 10 green,9 black ,6 red ,aball is chosen at random replaced then wht is the least possible no of draw u make so tht u will be confindent that u have atleast 2 balls of same colour a)7 b)6 c)5 d)3 e)1
there are three containers 1st=r,2nd=s,3rd=t.container 1 contain=1/4 content.container 2 contain=3/4 content.3=full.1 and 2 containers are put in 3rd container than it was asked to find the volume of 3rd container? cola colb r+s/4 16r+5s
option D
std.deviation of 6 set of number.each number in the set is divisble by 7 and 10 is added to each number then std deviation of new set is 0,7/10,10/7,10root7,7root10
a jar contains 20 marbles :4 red,6 white & 10 blue.if u remove one marble at a time,randomly,wat is d minimum no tat must me removed to be certain tat u have atleast 2 marbles of each color? a)6 b)10 c)12 d)16 e)18 ans is E
if the perimeter of triangle is 18,then the length of one of the sides CANNOT be?? A)1 B)3 C)6 D)8 E)9
i think the ans should be E as taking 9 we get the sum of other sides as 9 now rule is that the sum of two sides are always greater than the third side hence this cannot be the side of triangle ans. 9(E)
Seven similar 1\$ bills are to be distributed between three friends A, B, C such that each of them gets atleast 1\$. Column A : Number of ways of distributing the bills such that atleast one of them gets atleast 3\$ Column B : Total number of ways distributing these bills
The answer to the 1\$ bill question is C Both the probabilities are same.. in whatever way u distribute one guy will definitely get three 1\$ bills..
A right angled triangle ABC was given in which angle C is 90 degrees. BC=4, AD=3. D is a point on BC. Given that the perimeter of triangle ABD is equal to the perimeter of triangle ADC. Then find the ratio BD/DC Ans-1:3
A circle with Centre C was given, and there were two points A and B on the circumference of the circle. ABC form a triangle such that angle C is 90 degrees. Secant AB is shaded. radius of the circle, i think was two..given. This was a comparison question, column a : area of the shaded portion column b: 6 Solution:area of the shaded region i.e., d sector can b calculated as -->[x/360]*pi*r^2 -->[90/360]*pi*2*2 -->[1/4]*pi*4 -->pi -->3.14 vch is less thn 6 hence column b is greater
A jar contains 10 green, 9black,6red. a ball is chosen at ramdom replaced,then least possible no of to draw so that u will be confident dat u have atleast 2 are of same colour 7, 6, 5, 3, 1
Std.deviation of 6set of no. each no in the set is divisble by 7& then 10 is added to each no. then std. deviation of new set is 0, 7/10, 10/7, 10root7, 7root 10
4 boats were given co lour max capacity max weight red 4 800 green 2 340 blue 3 480 yellow 5 1200 it was given that there are 16 people and only 3 boats can be used .the boats are filled to their capacity .a person is picked ranmomly.wat is probability of him being in red boat?
n is multiple of 7 and n=(s^2)*t where both s and t are prime no’s . Which of the following will be a multiple of 49 ? options are s^2*t^2 , s^4 , s^2*t , etc
The answer i got was (s^2)*(t^2).
7k = s^2*t multiplying both sides by 7 49k = s^2*t*7 since we have assumed t to be 7, it becomes 49k = s^2*t^2 If t was not assumed to be 7, the answer would ve been 49k=s^2*t*7 or some k*t*7 2) P = number of values of t less than 100 are there ,for which t/10 is an even integer ? col A : P col B : 4 (Ans is D as he didnt mention +ve even integers) 3) perimeter of triangle is 32. two sides are 12 and 13. The angle opp to side 13 is 'X' col A : X col B : 90 degrees 4) if 5*t < 0 number then col A : 5t + 4 col B : 0
A set of six squares is given, they are arranges as a cross four vertical and 3 horizantal... from one end of the cross a diagonal is drawn to the other end!! now the diagonal length is 12, find the area of the whole set!! soln: first draw 4vertical square & 3 horrizontal thn join 2 end let side of square =x thn u vl get (3x)^2+(2x)^2=144 13x^2=144 x=3.33 thn find area of one square=(3.33)^2 =11.08 now multiply wth 6=11.08*6 =66.5
A taxi driver charges \$2.50 for first 1/4 of a journey... and \$2.00 for every 1/8th mile... then find the total cost of the m miles...(i do not remember the numbers correctly.. but the question was of this sort) soln: A taxi driver charges \$2.50 for first 1/4 of a journey... and \$2.00 for every 1/8th mile... then find the total cost of the m miles.. soln:first understand 1/4=.25 & 1/8=1.125 take m thn m -.25 m = 0.75m thn 0.75/0.125=6 (.125+.125+.125+.125+.125+.125=.75) therefore ans is=>> 2.5(1)+2(6)=14.5
John's weight is 10 pound les than 3 times the weight of his daughter Ann col A=avg of john' and Ann's weight col B =twice of Ann's weight
colubm B answer as let anu age =x then john =x-10 avg is [x+x-10]/2=x-5 and column B 2x always column B greater
Which of the following CANNOT be a factor of 2n. 3k, where n and k are positive integers? (A) 6 (B) 8 (C) 27 (D) 42 (E) 54
ans is D i.e. 42
coz, 42 = 2 X 3 X 7 = 2n.3k.7, where n=1 and k=1. other choices don't suit. for example let us take 27. 27 = 3X3X3. so, if k=9 and n is any positive integer say 1, then 2n.3k = 54. thus 27 is its factor.
.from the incoming freshman class at a certain college a gps of stu n was randomly selected for testing .for this gp of stu,the following is true: 1)group’s mean score is 1223 2)group’s SD is s. which value of "n" and "s" provide the strongest evidence that mean scores for the entire class exceeds 1200?? A)n=100,s=100 B)n=100,s=400 C)n=400,s=100 D)n=400,s=400
N is multiple of 7 and n=(s^2)*t whr both s and t are prime no.s . Which of the foll will be a multiple of 49? options are s^2*t^2 , s^4 , s^2*t , etc The answer i got was (s^2)*(t^2). n is a multiple of 7 and so s^2*t=7k, where k is some integer. since 7 is prime, s^2 cant be 7, so t should be 7 or its multiple. let us assume t was 7. 7k = s^2*t multiplying both sides by 7 49k = s^2*t*7 since we have assumed t to be 7, it becomes 49k = s^2*t^2 If t was not assumed to be 7, the answer would ve been 49k=s^2*t*7 or some k*t*7
of 30 applicants for a job, 14 had at least 4 years experience, 18 had degrees, and 3 had less than 4 years experience and did not have a degree.How many of the applicants had at least 4 years experience and a degree. ANS GIVEN ARE A) 14 B) 13 C) 9 D) 7 E) 5
ANS:E
There are 5 envelopes for prize distributions of which 2 contain cash n 3 contain certificates. when randomly 2 envelopes r taken without replacing one after other what is the probability of getting at least one envelope which contain cash.
Solution
There are 5 envelopes for prize distribution of which 2 contain cash n 3 contain certificates. when randomly 2 envelopes r taken without replacing one after other what is the probability of getting at least one envelope which contain cash. for this assume that all the two drawn are from certificates so 1-[all certificates drawn gets at least one cash] i.e., 1-[[3*2]/[5*4]]=7/10
cola product of two consecutive odd integers col b 0 verbal antonyms
metamorphism castigatio aversion amenity Mendacious Heresy Pulchritude Aesthete Analogies: index:page fence:livestock mirror:reflection affable ans-irascible then analogies enfeeble:strength quatrain:stanza
a circle was drawn inside the square of radius sqrt of 2 so what is area between 1 part between the circle and square(as there are 4 regions between the square and circle they asked one region....................hw to solve dis
ans
as given that radius is rt2 the side of square will be 2rt2 and now area of square - area of circle = area whis is left in suqare apart from circle == 2rt2*2rt2-pi*rt2*rt2 == 8-pirt2 now as we have 4 equal parts divide by 4 gets the area of that region ans = 1/4[8-pi rt 2]
X+Y>X-Y X+Yfor this let x+y>x-y , x+y0 and 2x<0>0 and 2xy<0>0 and xy<0 so answer D
A necklace is made by stringing N individual beads together in the repeating pattern red bead, green bead, white bead, blue bead, and yellow bead. If the necklace design begins with a red bead and ends with a white bead, then N could equal (A) 16 (B) 32 (C) 41 (D) 54 (E) 68 e
In a certain pond ,59 fish were caught, tagged and returned to the pond .a few days later,50 fish were caught again, of which 2 were found to have been tagged .if the %of tagged the second catch appox the %of tagged fish in the pond, what is the appox number of fish in the pond? 400 625 1250 2500 10000
G gallons of water in a tank, if X gallons/hr--water flowing inward,Y gallons/hr water flowing outward, condition Y>X..then how much time it takes to so that the tank capacity becomes G/2 gallons of water.
Let us assume that G=20 gallons X=5 Gallons/Min Thats In Y=10 Gallons/Min Thats out so 10 out 5 in means 5 out so 20-5-5=10 Gallons in 2 minutes So 10 option g/2(y-x) will satisfy the answer.....
. there are three '*', two '?' and one '\$'in how many ways we can arrange the symbols in 6 places(eg: *\$?**? )

three *, two ?, one \$ all togehther we have 6 sym. we can arrange 6 sym in 6 places in 6! ways... buttt here 3 sym(*) are of same kind n 2 sym(?) are of same kind.. so ans..... 6!/(3!*2!)= 60..
OR
see the ans is 60 only...many ways we can solve wat ever way u do u will end with 60 there are altogether 6 symbols... so if u put the \$ in the first place, then u have 5 places remaining with that fill 3 places with *..now 4 places are occupied so remaining places is 2...with that fill the 2 ?... so 6C1 * 5C3 * 2C2 try different possible varieties u will end up with 60 only...
..A taxi driver charges \$2.50 for first 1/4 of a journey... and \$2.00 for every 1/8th mile... then find the total cost of the m miles... sol: 2.5+12m exp:lets assume m=1 then for 1/4th journey it costs \$2.5 n remaining is 3/4th journey.. given for every 1/8th journey after 1/4th journey it costs \$2.00 so (3/4)/(1/8)=6 total cost= \$2.50+6*\$2.00 if we take m=2,, total cost= \$2.50+2*(6*\$2.00) for m=3,, total cost= \$2.50+3*(6*\$2.00) for m miles total cost =\$2.50+m*(6*\$2.00)
A can complete a work in 10 days, B & C take 15 & 20 days resp. to complete same work if A starts the work and works at it for 1 day than B & C joins and A leaves & both work 2gether for 1 day & than B leaves. How long will C take to complete the work??
If A completes a work in 10 days.. he completes 1/10 of the work in a day..
similarly 1/15 for B and 1/20 for C so now.. A works for a day --> 1/10 of the work is done B & C work 2gether for 1 day --> 1/15+1/20 =7/60 of the work is done work completed = 1/10+7/60 = 13/60 of the total work work remaning = 47/60 Since C completes 1/20 of the work in 1 day, C will take (47/60)/(1/20)=47/3=15.66 days to complete the work.

k consists of p1,p2,p3,p4 numbers and L consists of p1+4,p2+4,p3+4,p4+4 numbers col a col b std deviation of K std deviation of L
There is one circle ,square is inscribed in that circle,there is one more circle inscribed in that square...find the ratio of area of outer circle to inner circle
4 boys and 4 girls sit in a row at random. The probability that 4 girls sit together is A) 1/14 B) 1/12 C) 3/7 D) 9/13 E) 10/13
There are totally 8!/(4!*4!)=70 of arranging the 4 boys and 4 girls and there are five ways in which all the girls can sit together..following is the expln they could all sit starting from 1st position or 2nd or 3rd or 4th or 5th i.e total five ways so probability of them sitting together is 5/70 =1/14
Or
yes 1/14 is right.. 5 (favourable events)/ 8 C 4 (total events) = 5/70 =1/14
A circle was drawn inside the square of radius sqrt of 2 so what is area between 1 part between the circle and square(as there are 4 regions between the square and circle they asked one region)
2. 120Solve it
x < 0 and y < 1
Column A x-3y Column B 0 Column A is greater Column B is greater Columns A and B are equal The relationship cannot be determined
ans is b
ok people..try this x<0 x =" -1" y =" -1"> 0 (=> A) for x = -1 & y= .5....expression -1 - 3(.5) = -.5 <0>B) there fore anwer is D
which of the following is not the sum of three consecutive odd integers ? A - 9 B - 33 C- 255 D- 313 Ans D-313. Other question r already appeared in july quant thread such as... 1) g gallon of water ... y> x Ans - g/ 2y-2x 2) n is a positive integer
column a : sum of odd integers betn 100n and 200n both excluding column b : sum of even integers betn 100n and 200n both excluding Ans : A.> B
3) n is greater than 2 and it is an integer 5 [ 2^ n+1 - 2^n ] > 20 column a : n column b : 4 Ans : D cant determined. 4) A circle was drawn with center at 'O' with diameter AC. make the point B on the circle which make the tringle ABC in semicircle with angle B 90. AB = 6 and BC = 8. now point B was connected with center O which make the line BO and asked to find the length BO in column a and 5 was in column b. just make the diagram ...u will find r=5 which is actuly the length of BO being radius. so, both the columns are equal. ans = C 5) perimeter was given of right angle isocles tringle 1+root 2 . find area. Ans = 1/ 4
k = y / x and k = 1/x + 1/y ; express k in terms of y a) 1/ y-1 b) 1/y+1 c) y/y+2 d) other options I don’t rem
the answer is opt A..... 1/y-1
col A col B (-2)^-3 (-4)^-3 is anwer is b
ya and that std dev sum col a col b std dev of y1,y2,y3,y4,y5 std dev of y1+5,y2+5,y3+5,y4+5,y5+5
hey i got that std dev sum,its ans is c
4 If k is a positive integer and if the numeral in the decimal system that represents the product 60k contains only the digits 0 and 2, what is the least possible value of 60k ? (A) 220 (B) 2,020 (C) 2,220 (D) 20,020 (E) 20,220
answer for k solving prob is C(2220)
A rectangular tank 10″ by 8″ by 4″ is filled with water. If all of the water is to be transferred to cube-shaped tanks, each one 3 inches on a side, how many of these smaller tanks are needed? 1. 9 2. 12 3. 16 4. 21 5. 39
ans is 12.
On a certain scale of intensity, each increment of 10 in magnitude represents a tenfold increase in intensity. On this scale, an intensity corresponding to a magnitude of 165 is how many times an intensity corresponding to a magnitude of 125? (A) 40 (B) 100 (C) 400 (D) 1,000 (E) 10,000
it's 10000 coz u have to do that on the above mentioned scale.. for every increase in ten there is a tenfold increase from 125 to 135 the increase is 10 for 145 the increase is 10*10 likewise for 165 the increase is 10*10*10*10 i.e. 10,000
Seven one dollar bills are to be distributed among A, B, C so that each person receives at least \$ 1 Col a: No. of to ways to distribute bills so that atleast one person received at least \$ 3 Col b: Total no of ways to distribute the bills
suppose A B C they always have 1 \$ so now out of 7 only 4 is left the different ways to split the with initial 1 wlld be 1 1 5 1 2 4 1 3 3 so everytime u distribute it , someone wld always have above 3 so the answer is C equal
f(x)=x+1/x which of them is right f(x)=-f(x) f(2x)=2f(x) f(1/x)=f(x).....like this some functions are given
given a rectangle with perimeter 20 and a triangle was given inside rectangle ,the base of triangle is same as the length of rectangle and height of triangle touching at the other side of length at some more than half of side........wat is d area of triangle....? its pretty simple if u see the figure....... sol is: 2(l+b)=20 l+b=10 l=6;b=4 area of triangle is 12........bcoz this option satisfies
140<=cd<=150 which is neither c or d options : 25 21 17 15 answer to this is 17 as cd is from 140 to 150 25 and 15 ok for 150 21 ok for 147 for 17 no.shud be either 136 or 153 so ans is 17 let me know urs view....
10 July questions Hi....gave GRE today. got 1450. V:650 Q:800 It is not difficult to score 800 in quant. The questions from the thread are consistently repeating. The database is rumoured to change smwhr arnd 18 July. My questions were
.A triangle is inscribed in a circle. Base of triangle=base(length) of rectangle, height of triangle=height(breadth) of rect.Perimeter of rect. is given as 20.Find area of triangle. Ans: 12 (we hav 2 tak l=6, b=4 for rect.) 2.A circle is inscribed in a square. (QC) col A: 3 times area of the region bet. square & circle. col B: Area of circle Ans:B 3.G gallons of water in a tank, if X gallons/hr--water flowing inward,Y gallons/hr water flowing outward, condition Y>X..then how much time it takes to so that the tank capacity becomes G/2 gallons of water. A) g/(2x-2y) (B) g/(2y-2x) (C) (2x+2y)/g (D) (2x-2y)/g (E) x+y/g Ans:B 4.A line passes through (3,1) and (5,-1). Another line k is perpendicular to this line. (QC) col A: slope of line k col B: 1 Ans:C 5.0s, if 25 nos have mean n and median l, n>l, then if the two sets combined of 40 elements has mean c and median d (QC) col A: c col B: d Ans:D (my frnd gt same q. wit mean & std. dev....for tht too ans wil b D) 10.if 1000 cubic inches of water flow in a cylindrical tank per min and the water level rises by 0.01 inches in one min.find the radius of the tank Ans: 180
11.There are three '*', two '?' and one '\$'in how many ways we can arrange the symbols in 6 places(eg: *\$?**? ) Ans: 60 12.There is a series x1,x2....xn Now c is added to each element to form new series x1+c, x2+c......xn+c col A: std dev. of series x1,x2....xn col B: std dev. of series x1+c, x2+c......xn+c Ans:C
13.There are 86 students.Some are placed in 5 rows of x students each. Others are placed in 4 rows of y students each. The remaining are placed in 2 rows of (y-2) students each. (QC) col A: x col B: y Ans:D (finally we gt an equation 5x+6y=90 wich can b satisfied by various values of x & y. Hence D)
{
sorry ....thts a mistake .....tri. inscribed in a rectangle .....mistyped it....sorry guys}
14. When 2/7, what is the 57th term in the quotient after the decimal point? a.2 b.8 c.5 d.7 e.1 Ans:B(5)
15. There are n numbers with a value of 8 each and n+2 numbers with a value of 10 each. What is the average(arithmetic mean) of the entire set of nos. Ans:9n+10/n+1 16. A quadrilateral ABCD having sides 10,10,1,9 is given. The angle between the sides 10,10 is x. col A:x col B:60 Ans:B
For the tri. inscribed in rect. q...u can tak l & b as anything ...(5,5) (6,4) (8,2) ...u can take any combi. bt ans. is 12 bcoz among all d options d only option satisfying d criteria ws (6,4)....so area of tri. comes out 2 b 12.....kuch samjhe .....i directly gav d answers. bcoz i dnt rem al d options ......
Jul 11
2.A circle is inscribed in a square. (QC) col A: 3 times area of the region bet. square & circle. col B: Area of circle Ans:B take the side of the square as 2x then the radius of the circle would be x Area of circle =pie*x*x area of square =4x*x so the 3 times the area between square and circle =x*x(4-pie)*3 which is less that pie*x*x therefore answer is B got it????
col A:100210x90021 col B:1000210x90210 In such q's....first consider the smaller no., ie compare 90021 & 90210. Now, check which is greater among these 2......90210 is greater . Therefore, col B is greater.This is the general logic for such q's. U can chk on d calci....ull find im right. try for diff. nos. 2 verify. (The col. in which the smaller no. ie, 90021/90210 is greater is the greater col.)
if all sides of a parallelogram are 6.then area is less than 36 right??? if all sides of a parallelogram were 6, then wudnt it be a square? or a rombus/?
it wud only be a rhombus... not a square
acc to me d area shud b less than 36...since area of parralelogram is base *height...i.e 6 * h(which is lil less than 6) correct me if i am wrong
yeah true i made a silly mistake.square or a rect stretched at an angle ll always ve a lesser area..sheh! sorry guys
Oil costs \$4 per gallon and diesel costs \$5.24 per gallon. If the price of oil rises at 10% a month, and the price of diesel is unchanged, how many months will it take until a gallon of oil costs more than a gallon of diesel? Ans – 3
a parallelogram ABCD with sides 1 each is divided such that 2 > equiletral triangle forms now find distance of longest side i.e AC
The side AC will be equal to 1. AC is the common side and it has to be equal to the other sides of the triangle AB and BC. AB and BC are also side of the parallelogram. AB=BC=AC=1.
OR
longest side is the trick word here. If the side is longer than 1, the triangle is not equilateral anymore. the angles of the parallelogram will be 60,120,60,120. So, AC will be the digonal joining A and C ie the two 120 degree angles. hence the parallelogram is split into two equilateral triangles. Trying drawing a figure
Approximately how many revolutions will be made by a bicycle tire with a 14-inch diameter if the bicycle travels 1/2 mile? (12 inches per foot and 5280 feet per mile. Assume pi is 3.14).
the circumference is 2*pie*7=43.96 and the distance is (5280*12)/2=31680 so the revolutions = 31680/43.96=720.something so answer shud be 721.. wats ur method?? reply fast
It takes three laborers ten hours to install four faucets (each faucet takes the same amount of work to install). How many hours would it take nine laborers to install twelve faucets?
the same time i.e. ten hours.. coz the numbers have changed proportionately..
IF P,Q,R are the integral multiples of 3,5,7 and if P=R and PR<2Q then the relationship between lowest values of P and Q a)Q=P+49 b)Q=p-49 c)q=p-3/7 d)p=q-204 e)p=q-63 since we want lowest values of p therefore 21 is the least value such that p=r and p,r are integral multiples of 3 and 7 substituting 21in pr<2q we get q's least value as 225 therefore option D is correct
if y is a multiple of 6 and divisible by 77 then y/21 is divisible by which of the following?? ans. 22
The cost of a cup is twice that of saucer. if the cost of cup incresase by 13% and that of saucer is increased by 19% by how much % would the cost of 6 cups and 6 saucers increase. a) 7% b) 7.5% c) 15% d) 16% e) 16.5%
a vendor sells some big baloons n some smaller ones.... he sells big baloons at a rate of 50cents more than thrice d rate of smaller baloons: Column A: Mny earned by selling 100 small n 100 big baloons Column B: Mny earned by selling 130 big balloons
How many integers between 1 and 2000 inclusive are both the squares and cubes of any integer 1.3 2.4 3.12 4.21 5...dun remember
12 is correct because 21^3 is > 2000
the ans is 12. Try finding the cube of each of the options, it ll be seen that only for 21, it exceeds 2000, so the ans should be one immed below 21. So hopefully its 12. Its just guess work when we dont ve a calci. I dont know a proper method. If someone else knows, please enlighten us.
a man sold product X for 25% profit and Y for 25% loss..if he sold them for 210000 each then the sum of their original products is how much greater than 420000? 1.0 2.14000 3.36000 4.42000 5.28000
ans 28000
x is the largest number so that 6^x is exactly divisible by 252^5. Column A: x Column B: 10 i think col A is greater, since its said, x is the largest no. for any current value of x such tat 6^x is divisible by 252^5, we can always have a larger value of x, say x'=k*x, where k is some positive integer, so that 6^x' is also divisible by 252^5
If X is prime and N × X is both the square of an integer and the cube of an integer, where N is a positive integer, what is the greatest possible value of 1/(N × X) ? I am getting the ans as 1/64. Let me know if you find some discrepancy in my method. for 1/(N x X) to be greatest, (N x X) should be least. Say X=2, a prime we need NxX which is both a perfect square and perfect cube. 64 is the first no, which is a perfect square and a perfect cube. also N=32 is a positive integer. so ans could very well be 1/64
11th july quant hyderabad today i wrote my exam got 790 in quant. DI was a bit difficult. some of the questions i could remember (1) In a company 20% are male's ,60 new people are added to the company of whom 50 are male's,the ratio of male's isto female's before adding the 60 people is 1:4. the ratio after adding 60 people is 1:3. total no. of employees in the company? a)700 b)840 c)360 other options i don't remember
Here is the solution. Let total number of employees be T now, as per intial condition, number of males = 20% of total => M = T/5 and initial number of feamles : F = 4T/5 {given ratio of male to female s 1:4} now when 60 new workers are added 50 are male and 10 are female: Therefore.. M' = (T/5) + 50 = (T+250)/5 F' = (4T/5) + 10 = (4T + 50)5 new ratio is 1:3 therefore : (T +250)/ (4T+50) = 1/3 solve & u'll get T = 700 (2) x-2<2 find the range of x? ans:0can any one explain me this i do have exam tomm itself (5) the cost of X books is \$1.00 and the cost of Y books is \$3.00. total cost of sales of the books is \$336.00. what is the max. no. of books that can be sold on that day? a)22 b)20 i don't remember other options
X+3Y = 336 we shld find max of (X+Y) = 336 - 2Y Y shld be minimum for 336 -2Y to be minimum so max no .of books sold is 336
how many integers between 1 and 2000 inclusive are both the squares and cubes of any integer 1.3 2.4 3.12 4.21 5...dun remember d ans is 3 cube= 1,8,27,64,125,216,343,512,729,1000,1331,1728 sqrs= 1,64,729 <1^2,8^2,27^2>
answers to my prev post are 1)ques hav some prob 2)modulus id always positive so -2< (x-2) <2 0if 1000 cubic inches of water flow in a cylindrical tank per min and the water level rises by 0.01 inches in one min.find the radius of the tank Ans: 180
volume is 1000 rise is .01 here is vol of water =pi r^2 h ie this becomes a small cylinder of ht, h 1000/pi h =r^2 round abt comes to b 178solve above equation
the cost of a cup is twice that of saucer. if the cost of cup increases by 13% and that of saucer is increased by 19% by how much % would the cost of 6 cups and 6 saucers increase.
a) 7% b) 7.5% c) 15% d) 16% e) 16.5%
ANS is (c). = 15 %. SOL :- let initial cost of CUP = C. SAUCER = S. then initially C=2S.........................................................(1) now new cost of CUP = 1.13C SAUCER = 1.19S now consider the case of 6 CUPS n 6 SOACERS : intial cost 6(C+S). final cost 6(1.13C + 1.19S). so % increment in the value of these items = [final cost - initial cost] / [initial cost] X 100. = 6[1.13C + 1.19S - C-S] / 6[C+S] X100 ={.13C + .19S}/{c+s} X100 using equ 1: = {.26S + .19 S} / 3S X100 =45S/3S =15%
OR Start off by assuming the prices.. cost of cup:20 and cost of saucer:10 Calculate the cost of 6 cups and 6 saucers before the increase of price. 6*20+6*10 = 180 Cost of cup increased by 13% ie.. 2.6 that sums up to 22.6 cost of saucer increased by 19% ie.. 1.9 that sums up to 11.9 Now calculate the cost of 6 cups and saucers considering the increased cost. ie.. 6*22.6+6*11.9 = 207 The total cost increased from 180 to 207 thus a increase of 15% .
The price of book x is 5 times the price of book y. On a particular day, y books were sold as many as 4 times x books thus making business of \$36. What is the cost of x book?
x=12/7
).pi,2pi,3pi------- is a series col a : ratio when x is divided by number preceeding it col b: difference when a num preceedin x is subtracted fom x where x is any element in the series
answer is b coloum a is always less than 1 coloumn b is always pi
11th july hey guys gave my GRE yesterday have got some sums for u 1) If -1Of 5 households in a certain region, 3 households have exactly two cars each. If this proportion holds true throughout the region, how many of the 3,000 households in the region have exactly two cars each? (A) 1,200 (B) 1,800 (C) 1,803 (D) 1,997 (E) 2,000
The cost of sending a package special delivery is x cents per ounce up to 10 ounces and y cents for each ounce in excess of 10. Which of the following represents the total cost, in cents, of sending special delivery a package weighing w ounces, if w > 10 ? (A) x + (w – 10)y + 10 (B) x + (w – 10) + y (C) 10x + 10(w – y) (D) 10x + y (w – 10) (E) 10x + w y
10 x +wy
When it was found that 150 more tickets for the school play were sold than the seating capacity of the auditorium, it was decided to have two performances. If the total number of tickets sold was equal to the total number who attended and if the auditorium was full for each of the two performances, what is the seating capacity of the auditorium? (A) 100 (B) 200 (C) 225 (D) 300 (E) 450
RESULTS OF USED-CAR AUCTIONS X AND Y Auction X Auction Y Small Cars Large Cars Small Cars Large Cars Number of Cars Offered 32 23 38 37 Number of Cars Sold 16 20 18 29 Projected Sales Total for Cars Offered (in thousands) \$70 \$150 \$60 \$230 Actual Sales Total (in thousands) \$41 \$120 \$28 \$160 At auction Y, the number of small cars sold was approximately what fraction of the number of small cars offered? (A) (B) (C) (D) (E) The correct answer is (D)
The entries in a flower show competition are 2 orchids, 4 roses, 3 tulips, and 2 violets. If a first-prize selection consists of one flower from each of the four categories, how many different first-prize selections are possible? (A) 11 (B) 24 (C) 48 (D) 96 (E) 576
Sixty-eight people are sitting in 20 cars and each car contains at most 4 people. What is the maximum possible number of cars that could contain exactly 1 of the 68 people? (A) 2 (B) 3 (C) 4 (D) 8 (E) 12
The odds that a certain event will occur is the ratio of the probability that the event will occur to the probability that it will not occur. If the odds that Pat will win a prize are 4 to 3, what is the probability that Pat will not win the prize? (A) 1/4 (B) 1/3 (C) 3/7 (D) 4/7 (E) ¾
In an election each voter voted for one of two candidates, X and Y. The number of votes that Candidate X received was more than the number of votes that Candidate Y received. Column A Column B The fraction of the total vote that Candidate X received (A) The quantity in Column A is greater. (B) The quantity in Column B is greater. (C) The two quantities are equal. (D) The relationship cannot be determined from the information given.
(x-4) (X-2) = 1, A B value of X 4 ans D
A quadrilateral ABCD having sides 10,10,1,9 is given. The angle between the sides 10,10 is x. col A:x col B:60 Ans:B
There are n numbers with a value of 8 each and n+2 numbers with a value of 10 each. What is the average(arithmetic mean) of the entire set of nos. Ans:9n+10/n+1
There are n numbers with a value of 8 each and n+2 numbers with a value of 10 each. What is the average(arithmetic mean) of the entire set of nos. so there are two sets A {8,8,8,8,....n times} B{10,10,10...n+2 times} total value of A = 8n and total value of B = 10(n+2) now trying to take arithmatic mean= sum of values of numbers / total numbers = 8n+10(n+2)/(n+n+2) = 18n+20/2(n+1) =9n+10/n+1
col A :s.d of x1,x2,x3,x4 colB :s.d of x1+5,x2+5,x3+5,x4+5
ans to first is C 2)Col A ------ w ( 2x +2y + 2z + 1 ) Col B ------ 2w ( x + y + z ) ans:C lcm of k , m is k*m lcm of m , n is m*n col A ------------------ col B lcm of k , n -------- k*n
ans: D
take any values say k = 3 m = 4 n = 5 A = 12 B = 20 in this case B now take k=8 m = 4 n = 2 A = 8 in this case A B= 4 hecen answer is D 4>N is any +ve integer below 100 how many numbers below 100 wen divided by 10 gives an even integer i.e N/10=even int A)4 B)6 C)7 d)9 e)8 answer for the 4 th ques is C 5> 20.IF P,Q,R are the integral multiples of 3,5,7 and if P=R and PR<2q q="P+49" q="p-49" q="p-3/7" p="q-204" p="q-63">pi,2pi,3pi------- is a series col a : ratio when x is divided by number preceeding it col b: difference when a num preceedin x is subtracted fom x where x is any element in the series
Ans:B
for col A...take as 2pi/pi=2,3pi/2pi=1.5,4pi/3pi=1.3....so max value ll be 2 nd for others it will be 1.something... for col B... 2pi-pi=pi(2-1)=pi=3.14,then 3pi-2pi=pi(3-2)=pi=3.14...so here the value is 3.14.. so col B is greater....
((((((((((ans. for above ques. are: 1) C 2) C 3) dont know 4) C 6) 3 7) 4*sqrt(3) *pi))))))))))
A tank can be filled by a tap in 20 min. and by another in 25 min. Both the taps are kept open for 5 min. and than second is turned off. In how many minutes more is the tank completely filled?? a) 9 min. b) 11 min. C) 10 min. D) 12 min.
ans B
A quadrilateral ABCD having sides 10,10,1,9 is given. The angle between the sides 10,10 is x. col A:x col B:60 Ans:B sol:-draw digonal b/w sides 10,1 & 10,9 now size of digonal will always be less than sum of other two sides it will be less than 9+1(i.e<10) now consider triangle 10 ,10 &digonal(<10) since size of dig. is less than other two sides anle opp to it will be less than other two i.e <60
in a certain examination 35% of the students failed in Maths and 20% failed in Chemistry.10% of students failed in both Maths & chem. find the no.of students who failed only in chem,if the no. of students who passed in bothe the subjects is 110 plzzz......solve this urgently my GRE is on 17th of this month....... ANS is 20. let total stu. be X then .35X failed in maths, .20X failed in chem. and .1X failed in both. no of stu passed in both = total - failed ONLY in maths - failed ONLY in chem - failed in BOTH i.e. 110 = X - (.35X - .1X) - (.20X - .1X) - .1X => 110 = X{1- .25 - .10 - .1} => 110 = X{.55} => X =200. so stu that failed in chem only are: {.20-.10}X = .1X = 20.
Test questions
k = y / x and k = 1/x + 1/y ; express k in terms of y a) 1/ y-1 b) 1/y+1 c) y/y+2 d) other options I don’t rem ans. a 2. -1x b>x^3 c>x-1 D x^3-1 ans. b 3.col A col B w(2x+2y+2z+1) 2w(x+y+z) ans. a 4.140<= ab <= 150 a.13 b.15 c.17 d.21 e.22 ans.c 5.there are 3 '*', 2 '?' and one '\$'in how many ways we can arrange the symbols in 6 places(eg: *\$?**? ) ans.60 6.a merchant sold 1000 widgets with no profil or loss... for the next widgets he sold ffor a profit of 0.50\$ each... and now his total porfit is p. now calculate the whole profit he made including the 100 widgets! ans:2p+1000 7.a rectangular playground is divided 300x150sqft! and at the top 150ft and bottom 175 ft a line is cut..... and a concrete slab of 3inches thick is pored!! what is amount of concrete must be added to fill the trapezoid?? in cubic ft!! answer.61800 cu.ft!! 8.6 squares are arranged in the form of a cross. the diagonal from one end of a square which is arranged horizontally.to the other end is 20... find out the total area of the cross... ans = 240 9.water in flown into a cylindrical drum at the rate of 1000cu m in one minute.the height of water in the drum increases at a rate of 0.01mt in one minute.what is the dia. of the drum? ans.180 10.n is a multiple of 7.n is also equal to s^2t where s and t are both prime numbers less than 100..which of the following is a multiple of 49. a.(t^2)s b.(s^4) c.(s^2)t d.(t^2) e.(s^2)(t^2) ans. e 11.Xsq.feet = 150sq.yards(1yard=3feet) cola colb X 30 ans.B 12.a figure of a quadrilateral ABCD is given with sides AB=9,BC=9,CD=9,DA=1(the figure is deceptive.It looks like a triangle). angle ABC=60.Angle CDA=x cola colb x 60 ans.b
If 2 cubes each of edge 6cm are joined end to end whats the surface area of the resulting solid? (A) 420 (B)400 (C)360 (D)300 (D)260(all options r in cm^2) answer is 360..simple enough..total surface area will be 5 *12*6 = 360
2>How many spherical bullets of diameter 5mm can be made from a spherical ball of radius 5cm? (A)8 (B)80 (C)800 (D)8000 (E)80,000 answer is 8000.. equate volume of ball with 5cm radius to N times volume of 5mm diameter ball u'll get it as 8000
A cube has a volume of 72.If it's divided into 8equal cubes,the ratio of an edge of a smaller cube to an edge of the original cube? (A)1:2 (B)1:3 (C)1:3root2 (D) 2:9 (E)1:9 larger cube..volume = 72 => one side is cube root of 72 = 2cuberoot(9) smaller cube ..volume of larger cube/8 = 9 there fore sde of smaller cube is cuberoot(9) ratio of side of edge of smaller cube to hat of larger cube is therefore cuberoot(9)/2 cuberoot(9) = 1:2 therefore answer is A
gave mah GRE on 13th mah 1st question was maximum value for -x^2+y^4 where -6<=x<=3 and -10<=y<=6 options were 1.)1296 2.)1305 2.)10000 3.)10036 i wasted mah 5 mins on dis question and damn sure abt d options finally i marked d ans as 10036 and mah score in maths was 800
w(2x+2y+2z+1) 2w(x+y+z) =2wx+2wy+2wz+w =2wz+2wy+2wz subtracting 2wx+2wy+2wz from both the columns , you get w and 0 now w can be anything from -infinity to + infinity so the answer is D
2---For which interval on the number line, the product of any two numbers falling in the interval lies outside the interval? a)0 to 0.5, b) -0.5 to 0.2, c)-1 to -0.5 , dont rem the other...ans is c.
************one yr ago, a company has 1/4 of the members architects. during the yr 60 new employees were added out of which 50 were architects. the ratio of architects in the company changed from 1/4 to 1/3. find the no of employees that the company has at present?
let members in prev. yr = X no of arc. prev. yr = X/4 this yr. total members = X+60. total arc. = X/4 + 50. so X/4 +50 = 1/3(X+60). => X/3 - X/4 = 30 => X= 360. so no of members at present = X +60 = 360+60 = 420
420 guys
mod x = mod y, xy<0 and x,y are integers. cola colb x+y 0 ........think the ans is c..
line segment AB length 4 is parallel to x-axis. line segement CD length v (v>0) is parallel to y- axis. cola colb v 4 ans-d
m has p1,p2,p3,p4,p5 and N has p1+5,p2+5,p3+5,p4+5,p5+5. cola colb s.d of m s.d of n ans-c
a computer programme makes 5 letter passwords using 1 @sign, 2 #signs and 2 \$ signs and arranges them in any order, for eg @#\$#\$.. cola colb total no of such passwords 30 ans-c
The paswd prgm ans. is 30 only... since there are 5 symbols and two symbols r repeating...the formula is 5P5 divided by ( 2! * 2!) i.e...120/4 = 30
a person buys two types of books from a fair, x costing 1\$ and y costing 3\$ except these he does not buy any other book. if 0x^2+4x-5>0, cola colb x+4 5 here u get 2 values for x+4>-1 or x+4>5 after solving eqn. so ans d
a group of people were tested to check the vulnerability to a disease. 10% of those tested were found to be vulnerable and has age below 20 yrs. Out of those who were vulnerable to disease 60% were found to be over 20 yrs or 20 yrs old. Find out the ratio of the people who were vulnerable to the disease to those who were tested. dont rem options but ans ¼
ans to the disease question... suppose 100 people r tested so 10 will have disease and <20yrs.>=20yrs and 0.4x <20yrs of age. which means 10=0.4x so x=25=people having disease. people having disease:people checked will be 25/100=1/4
During a certain season, a team won 80% of its first 100 games and 50% of its remaining games.If the team won 70% of its games for the entire season, what was the total number of games that the team playes??
dear that was wrong.......i have got the sol 4 it........ 80+(x-100)/2=0.7(x)...solving this x=150.
After 2 females leave a party, there are twice as many males as females.Then 9 males leave and there are twice as many females as males. a)The total no of people left at the party after 9 males leave (or) b) 8
there are 9 ppl left at the party
. a new question came in which a hexagon was given with each side of 4. and a triangle was inscribed in it n we were asked to find the area of the remaining portion of the figure .... the options were 1.2root3 1.4root3 3.8root3 4.10root3 5.12root3 ans is 5. 12root3 soln. area of remaining fig will be area of the remaining 3 traiangles i.e 3 times the area of one of the remainig triangles now,consider 1/2 of one of the remaining triangles so,it will be a 30-60-90 degree triangle and one side is 4(hypotenuse) so,side2=2 (i.e height of triangle) and side3=2root3(i.e base) since a 30-60-90 degree triangle divides sides in the ratio 1:root3:2 so,area of the remainig fig will be=1/2*2*2root3*2*3=12root3 hopefully i made it clear....hehheee,i know its a bit tricky,especially witout the figure
a(n) = n!/(2n)! find a11/a10
the answer for u r que is 1/42 a11/a10= 11!/22!/ 10!/20! = 1/42 is it correct
verbal
Abate,Belie,Excise,Gall,PLummet:Fall
affable ans-irascible then analogies enfeeble:strength quatrain:stanza
castigate*laud metaphor*constant blanket*denude
how many 1 s r there in nos frm 1 to 300 ..both of them included??dont remebr the options.
no. of 1's between 1 to 300 is 160...the only correction from the aove person is that in between 100 and 200 there are 80 no.s...so the ans is 160...
If the sum of the two positive integers is 24 and the difference of their squares is 48 ,wht is the product of two integers a) 108 b) 119 c) 128 d) 135 e) 143 ANS 143. a+b=24 a^2 - B^2 = 48 =>(a+b)(a-b)=48 => a-b = 2 so a= 13 & b=11 therefore a*b = 143.
4 boys and 4 girls sit in a row at random. The probability that 4 girls sit together is A) 1/14 B) 1/12 C) 3/7 D) 9/13 E) 10/13 ANS 1/14 total possible ways : 8! /(4!X4!) = 70 (as there are 8 students of which 4 are of 1type ie boys n other 4 r of diff type ie gals.) ways in which gals can sit together = 5 (assume 4gals as a block n "each" boy as a single block, now u hav 5 blocks to arrange out of which 4 are of same type ie boys). therefore prob. = 5/70 = 1 / 14
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{ a jar contains 10 green,9 black ,6 red ,aball is chosen at random replaced then wht is the least possible no of draw u make so tht u will be confindent that u have atleast 2 balls of same colour a)7 b)6 c)5 d)3 e)1 a jar contains 20 marbles :4 red,6 white & 10 blue.if u remove one marble at a time,randomly,wat is d minimum no tat must me removed to be certain tat u have atleast 2 marbles of each color? a)6 b)10 c)12 d)16 e)18 ans is E}
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In a circle, two rt angles triangles ABC n ABD were inscribed with diameter as the hypotenuse. hope u can make out the fig.. cola colb area of ABC area of ABD is the ans:C ? rectangular cuboid with base 8x10 and height g and a cylinder with radius 10 and height h have equal volumes. cola colb g h is the ans:A ?
Hey for the cuboid and cylinder problem the answer is A... Solution.. as their volume is same 10*8*g = pi*10^2*h g=100*3.142*h/80 g=1.25*3.142*h so g must be greater than h
given nos from 1 to 40. set A contains multiples of 2 from 1 to 40 and set B contains multiples of 3 from 1 to 40. What is the no of integers which are in neither set? ans is 27
A : 2, 4, 6, 8 B : 33, 34, 37, 38 col A : Dispersion of A col B : Dispersion of B
Is "Dispersion" mean same as "Standard Deviation"? For the above prob, if u get the SD of both the columns, it is found that SD of A is greater than SD of B. So, is A is the answer? M bit confused, do the "Dispersion" mean same as "Standard Deviation"? Plz help.....
yes. SD is a way to calculate dispersion.
---(40)(75)(160)=3(4^x)(5^y) x and y r integers. cola colb x y ans:a yes or no
1)a quadrilateral with 4sides 10,10,9,1 and x is angle between 10,10. cola:x colb:90 2)some 1000 people wrote x and y tests. test mean rosea,s percentile x 260 400 90 y 200 360 x cola:x colb:90.
ans for qu 10 is C whenu solve both side u will ha ve 5^4*4^4=5^y*4^x ans for parallelogram is D ans for book qu is 16 u can buy 12 y books worth \$3 and 4 x books worth \$1
a person buys two types of books from a fair, x costing 1\$ and y costing 3\$ except these he does not buy any other book. if 0X is a negative number and x^2-25<9 Find the range: Ans is : -root(34)if x=-root(34), then 34-25=9, but we want <>-root(34) ..e.9. -root(33.9) gives 33.9-25 = 8.9 similarly if x=4 then we get 16-25= 9 , taking x<-4 e.g. -4.1 we get 4.1^2^2-25=8.19 Y^2 = X/4 Col A : X Col B: Y Ans : D Only 30 % of a class contributed to the school fund. If the average amount donated by each of these students is 1350\$, then: Col A: Average amount donated by each student of the class Col B : 450\$ Ans : Col B
The entries in a flower show competition are 2 orchids, 4 roses, 3 tulips, and 2 violets. If a first-prize selection consists of one flower from each of the four categories, how many different first-prize selections are possible? (A) 11 (B) 24 (C) 48 (D) 96 (E) 576
hey flower shiow answer is 48 2*4*3*2
Hey for that x and y books question costing 1\$ and 3\$ respectively....when you calculated for their maximum value you took y=x and got the answer as 20 which is wrong because they have clearly mentioned that y>x...so the solution is y=11 and x=7 i.e. 11*3+7*1 = 40 \$ so the answer to that question if maximum number of books is asked is...18...
The sum of three consecutive odd integers, x, y, and z , in ascending order, is 39. What is the sum of the three consecutive odd integers that immediately follow z ? (A) 78 (B) 57 (C) 48 (D) 45 (E) 42 b
odd no. after z,so starts from 17 17+19+21 so 57 ans.
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Two cars started from the same point and traveled on a straight course in opposite directions for exactly 2 hours, at which time they were 208 miles apart. If one car traveled, on average, 8 miles per hour faster than the other car, what was the average speed for each car for the 2-hour trip?
let av. speed of car1 = x and av. speed of car 2 = x+8. so av. speed of car 2 wrt car1 = 2x+8. now speed = distance / time => 2x+8 = 208 / 2. 2x+8=104 => x = 48miles / hr. so av speed of car 1 = 48 miles/hr. and that of car 2 = 56 miles / hr.
sum of three numbers(abc,bca,cab) is divisible by which of the following? a)110 b)111 c)112 d)113 ANS:111 2.If (s^2)t is multiple of 7 and s,t are prime numbers then which of the follwing will be multiple of 49? a)s(t^2) b)(s^3)t c)(s^2)(t^2) d)st
x= 2 to 30 col A=prime no.of x col B=1 anc. C
if 1000 cubic inches of water flow in a cylindrical tank per min and the water level rises by 0.01 inches in one min.find the radius of the tank
volume=1000 h=0.01inches pie r^2 h=1000....sub h as 0.01 n find r..v get it as 180..
a rectangular playground is divided 300x150sqft! and at the top 150ft and bottom 175 ft a line is cut..... and a concrete slab of 3inches thick is pored!! what is amount of concrete must be added to fill the trapezoid?? in cubic ft!! answer.61800 cu.ft!!
Jul 23(14 hours ago)
a rectangular playground is divided 300x150sqft! and at the top 150ft and bottom 175 ft a line is cut..... and a concrete slab of 3inches thick is pored!! what is amount of concrete must be added to fill the trapezoid?? in cubic ft!! for this prb..find the area of trapezoid and den by multiplying the area by thickness of concrete, we will get d amt of concrete required.. see dey hav given that at top 150ft and bottom 175ft.. so area wud be..A= 150/2 x (150 +175) , here 150 is the height of that section or the distance between 2 ll sides.. after this multiply area by 3inches = .25ft so final ans wud be... 150/2 x (150+175) x 0.25 = 75 x 325/4 = 6093.75cu.ft
find X
4^4x - 4^(4x-1) = 96 or, 4^4x - (4^4x)(4^-1) = 96 or, 4^4x - (4^4x)/4 = 96 or, 4^4x{1 - 1/4} = 96 or, 4^4x(3/4) = 96 or, 4^4x = 96(4/3) = 32X4 = 4X4X2X4 = 4^3 X 4^(1/2) or, 4^4x = 4^(3 + 1/2) or, 4x = 7/2 hence x = 7/8.
JULY 21
72.42=k(24+n/100), where k & n are integers & n<100, then k+n=? 17, 16, 15, 14, 13 plzz solve ..... then 72+0.42=k24+kn/100 and if u take k=3 then only u will get 72 integer and now u have to find the value of n=? that will give u 0.42 when u multiply it with k=3 so 0.42=3(14)/100 ans(k+n)=3+14=17. hope u got it.
40)(75)(160)=3(4^x)(5^y) x and y r integers. cola colb x y wats the ans..plzz solve ans is c '(4*2*5)(5^2*3)(4^2*2*5) this will give 3(4^4)(5^4) so ans is c
1)3^n+4 is divisible by 5,n= 23,24,25,26,27 Ans is 24 2)x+y>x-y & y+xif d1d2d3 are three positive integers and d1d2d3, d3d1d2, d2d3d1, so compare the S where s is sum of these three values Col A S Col B 111(d1+d2+d3) ans C words i got Fustian: Bumptitous Lamabaste, stolid, still:movement, sumptuous, malvolent, desist, antyonms ferocious metamarphosis ostracize anologies mirror:reflective glacier:ice bolster:support
1) lara in his 17th innings makes a score of 85 and thereby increases his average by 3. what is his average after the 17th innings? he had never been 'notout' a)47 b)37 c)39 d)43 e)45 ans:37 2) The average weight of 8 sailors in a boat is increased by 1kg if jack weighing 56kg is repleased by stefen. the weight of stefen is a)57kg b)60kg c)64kg d)62kg e)66kg
Ans64
On a certain scale of intensity, each increment of 10 in magnitude represents a tenfold increase in intensity. On this scale, an intensity corresponding to a magnitude of 165 is how many times an intensity corresponding to a magnitude of 125? (A) 40 (B) 100 (C) 400 (D) 1,000 (E) 10,000 plz explain
c just take any value...for example take 115 now 125-115=10 so thr is a 10 ka increase rite...this represents a tenfold(ten times) now 165-115=50 which is 5 times a tenfold and i.e. =100000 now take d ratio 100000/10=10,000 thus ya answer is E
Of the total no. Of days in week,what fraction of them occurs only 52 times in a leap year? A...........1/7 b...........2/7 c.............3/7 d..........4/7 e............5/7
for this ans wud be 5/7 see there r 365 days in a year.. 365/52.. 1 day remains..so in normal year any one 1 day frm the week cmes 53 times as far as leap year is concerned there r 366 days.. 2 days remain... so we can say 2 days frm the week cmes 53 times.. so only 5 days cme 52 times.. **** 5/7
if k is a positive integer and if the numeral in the decimal system that represents the product 60k contains only the digits 0 and 2, what is the least possible value of 60k ? (a) 220 (b) 2,020 (c) 2,220 (d) 20,020 (e) 20,220
for this simply divide d options given by 60 n find value of k..the least value for which u get k as integer is ans.. here its 2220..dats Ans) C
)on a day the pens sold in the afternnion were 4 times more than the pens sold in the morning . If the pens sold in the afternoon costs 90 \$ more thenm column a number of pens sold column b 90 answer is c both are equal
From 1 to 2000 how many of the cubes are eqqual to the no of squares!! ANS:12 (c) 26(d) 28(e) 30 Answer is 30
a isosceles triangle was given with 2 sides as x nd asked to find the range of y Ans:0 to 60
9.one question on Standard Deviation K--(p,2p,3p,4p...) R--(p+5. 2p+5,3p+5, 4p+5..) cola Standard deviation of K col b Standard deviation of R (ans c)
A ranch has horses and ponies. Five-sixths of the ponies have horseshoes. Half of the ponies with horseshoes are Icelandic. If there are three more horses than ponies, what is the minimum number of horses and ponies on the ranch? 12/15/27/48/54 ans is 27... if there r 12 den we cant divide in such a way that there r 3 more horses dan ponies..so this is not an option now say there r 15 in all...dat means 9 horses n 6 ponies..5/6 hav horseshoes ok so dat is 5..now half of these r Icelandic..we cant say 2.5 r Icelandic..so this is not option if there r 27 in total ...15 n 12 ...we get d ans
Given quadrilateral ABCD, AB=1, BC=9 (side opposite to angle x), CD=10 and DA=10. just imagine fig. col a col b x 60 answer is b
He said that...two tests T1 and T2 conducted.there were 1-1000 members and range of marks 0-500 given. T1 mean=250 rosa got 400 marks percentile=90 T2 mean=200 rosa got 360 marks percentile=x(???) col a col b x 90 i think answer is d
sum of 1 to 40 inclusive is 820.then sum of 41 to 80? cola colb sum of 41 to 80 2460 answer is b
if 72.42=k(24+n/100), where k & n are integers & n<100, then k+n=? a) 17,b) 16,c) 15,d) 14,e) 13
sorry its 72.42/3=24.14.Hence k=3;14/100=0.14;n=14.n+k=17.Dis is the ans answer a
3^n + 4 is divisible by 5 find the value of n a) 23 b) 24 c) 25 d) 26 e) 27 answer e
A box has three drawers; one contains two gold coins, one contains two silver coins, and one contains one gold coin and one silver coin. Assume that one drawer is selected randomly and that a randomly selected coin from that drawer turns out to be gold. What is the probability that the chosen drawer is one that contains two gold coins? Ans : 2/3
There are two mixture of wine and water, the quantities of wine in them being 1/4 and 3/4 . If 2 gallons of first be mixed with 3 gallons of the second the ratio of wine to water in the new mixture is a) 9 : 11 b) 11 : 9 c) 10 :13 d) 13 : 15
quantity of wine in the mixture: 1/4*2 + 3/4*3 = 11/4 quantity of water 3/4*2 + 1/4 * 3= 9/4 ans: 11:9
a 5-ltrs jug contains 4-ltrs of salt water solution that is 15% salt..if 1.5 ltrs of solution spills out of the jug,,n the jug is then filled to capacity wth water,,approximately what % of resulting solution in the jug is salt? a)71/2 % b)93/8 % c)101/2 % d) 12% e)15%
the answer for solution question is : 15 % solution in 4 lts = 600 ml solution after spillage = 600ml - (0.15)*1.5 lts = 600 - 225 = 375ml => solution percentage after adding water or solvent is = [ (375) / (5000) ] * 100 = 375 / 50 = 75 / 10 = 7.5 %
2) when a discount of 10% is given on goods being sold at a profit of 20%,,the number of units sold doubles.... col A col B ratio of previous profit to present profit 5/4 col a is greater here say the unit cost is rs100 so accounting 20% profit...selling price is 120..now on this price 10% discount is given..so now the profit is 108-100= rs 8 col a = 20/8 = 5/2...so col a is greater
A n B can seperately do a piece of work in 20 n 30 days respectively..they work together 4 sum time n then B stops..if A completes the rest of work in 10days..then B has worked for... a)6 days b)12 days c)16 days d)18 days e)20 days... for this i guess ans is 6days.. A and B wrk together for sme days..den B stops n den A completes remaining in 10 days. now A can complete half the wrk in 10 days..its given he completes the wrk in 20 days.. so we can say that...A and B together finished half the wrk.. dat means 1/2 = (x/20 + x/30)..so x cmes out to be 6....
The answer is correct by giri
there are types of balloons , smaller and larger ones... the cost of larger balloons is 50 cent more than three times the cost of smaller balloons column A : Total cost of 100 smaller and 100 larger balloons coulmn B: cost of 130 larger balloons Ans: D
------------------------- 3/64 T 7/16 column A : T column B : 9/32 Ans C
There are four grps of people.The grps consist of 5,4,6 and 8. there are 2 modes of transfer.A van which can take max. 6 and a car which can take max 4 at a time. During a single journey, these vehicles can carry people from only one group at a time. Column A The no of trips required to transfer all the people from one point to another using only the van. Column B The no. of trips required to transfer people in the 3 groups with the lowest no. of people using only cars. ANS: C
There are five integers.3 of them are below 20 but more then 10 and 2 of them are below ten. col a: arithmetic mean of these 5 integers col b: median of the integers which are greater than 10. sol: arithmetic mean of 5 integers. take no's as 19,19,19,9,9. then the avg of these 5 no's is 15. so the ans is D.
*A quadrilateral ABCD having sides 10,10,1,9 is given. The angle between the sides 10,10 is x. col A:x col B:60 Ans:B let AB =BC=10 AND angle x bet these two... now sum of other two sides is 1+9=10 tat means if we join A AND C then its length must b smaller than 10 therefore tringle abc cann t be equilateral and oppostie side is less than 10 so angle x be less than 60 hence ans is B
wat is the largest value of n such that 252^5 is divisible by 6^n cola- n col b-10 ans C
my st question was some number=35*77/1*x(not getting exactly iam srry) damn easy every one can do it ans is 231
some figure was given with 2 circles and triangle mixed its quite easy to tackle if u look keenly..asked to find the ration... ans is: 1:2
)k is any odd number greater than 100.d is divisor of k other than k. cola colb d k/2 ans is B
4^3y-4^3y-1=96 wat is the value of n..... ans is :7/6
col a = number of months from jan 1961 to dec 1885 col b= number of min in 5 hours. ans C
7)if an integer N is dived by 11 then the remainder is...(dont remember) if (N+1)^2 is divided by 11 then wat is the remainder ans 3 8)the perimeter of a right isoceles triangle is 1+root2.what is the area of the triangle? 9)A circle passes through the points (0,2) and (2,0). Col A : circunference of the circle Col B : 4pie ans is C 10)Certain no. of people were being checked for a certain disease. It was found that 10% of them were below 20yrs and had that disease. It was also found that all the people who were found to have that disease, 60% of them were 20 or above 20. Find fraction of people who were found to have that disease.. 1/2,1/3,1/4,1/5,1/6 ans is ¼
a quadrilateral is given abcd b=d=90.ab=8.bc=6.cd and ad are equal. cola colb cd+ad 10rt2 ans is C 16)p can take only these four values and the probabilities of taking the four values are given value prob 2 .27 4 .14 6 .38 8 .29 wat is probability that p takes a value less than or equal to 6?? col a- .. col b-... ans is B 17)employees and architect question also cam ans 420 18)two points (5,0) (0,5) equidistant....was also asked ans is D(QC question) 19)a circle with c1=2pi and other circle with c2=6pi wat is ratio of area of c1 to c2 ans 1:9
4^3y-4^3y-1=96 wat is the value of n..... ans is :7/6
the odds that a certain event will occur is the ratio of the probability that the event will occur .if the odds that part will win a prize are 4 to3,which is the probability that part will not win the prize 1/4 1/3 3/7 4/7 3/4 ans 3/7
x and y are integers and x-y is an even number.. col a : remainder when x^2+y is divided by 2 col b: 2 ans. b... jus plug in numbers n u get it easily.. dont try to do it algebraically
the average of x,y,z is 1/3 greater than x.the sum of y+z is what %greater than x ans. x+y+z=3(x+x/3) x+y+z=3x+x y+z=3x hence y+z is 200% greater thn x
its actually five ticks at equidistance... so the value at first position is 3/64 and the value at last i.e fifth postion is 7/16 so whats the value at 3rd position of the tick... Solution: multiply 7/16*4 i.e 28/64 now take the difference b/w first and last i.e (28-3)/64 = 25/64 , now divide it into 5 equal parts so the value at third part will be 3+5+5+5 = 18/64 which comes to 9/32 and that is what column B is So ANSWR IS C.....
there r 4 types of canoes.. red blue yellow green.. they have capacity of 3,2,4,6 ( not necessarily in tht order) 3 canoes are used to accomodate 16 ppl..wots the probability tht a person randomly picked is from the red canoe (whos capacity was 4).. here the only possible combination we can have is 2 canoes with capacity 6 n one with 4 (the red one) .. so the probability is 4/(4+6+6).. thts ¼
in give quadrilateral ABCD C=90 A=90 AB=BC CD=8 DA=6 cola: AB+BC colb: 10root2 ans is "c"
a circle with c1=2pi and other circle with c2=6pi wat is ratio of area of c1 to c2 ans 1:9